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Re: Problems with Problems
Posted by Louis Feng on December 27, 1998 at 11:34:27:
In Reply to: Problems with Problems posted by Jon on November 05, 1998 at 11:29:40:
I don’t know if you already forget, but you have gone to our web site—Trigonometric Identities at http://library.advanced.org/17119, and you have posted a question.
I weren’t able to check our site during that period. One of our friends sent us an email to notify me. so here is the answer.
csc^4A – cot^4A = csc^2A + cot^2A
L = (csc^2A + cot^2A)(csc^2A - cot^2A) (here csc^2a – cot^2A = 1)
Hope this will help. Thanks for visiting our web site.
: I just can't seem to do anything to this trig identity
: I just end up with cos'2A=1/2, can't prove it!!
: an email response would be appreciated.
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